Problem in using fsolve - MATLAB Answers - MATLAB Central
-1.0*1.25e-3*X(1) 1.0*1.66e-5*X(4) 1.0*4.47e-5*X(5) 1.0*1.07e-4*X(6); ... 1.0*807362.4375 -1.0*0.4*rho*X(4)^2 -1.0*X(11);. -1.0*0.4*rho*X(1)^2 ...
Problem in using fsolve - MATLAB Answers - MATLAB Central - Related Phones
-1.0*1.25e-3*X(1) 1.0*1.66e-5*X(4) 1.0*4.47e-5*X(5) 1.0*1.07e-4*X(6); ... 1.0*807362.4375 -1.0*0.4*rho*X(4)^2 -1.0*X(11);. -1.0*0.4*rho*X(1)^2 ...
... sum = 1.3744e 11 ans = 37 sum = 2.7488e 11 ans = 38 sum = 5.4976e 11 ... 1.1043e 71 ans = 236 sum = 2.2086e 71 ans = 237 sum = 4.4171e 71 ans ...
24 Nov 2017 ... p12 = -3.538e-05 ;%(-0.0003742, 0.0003035). p03 = -0.0001129 ;%(-0.0004093, 0.0001834). p40 = 5.228e-08 ;%(-1.143e-06, 1.247e-06).
... number of pages A = rand(M,K,'gpuArray'); B = rand(K,N,P,'gpuArray'); C = pagefun(@mtimes,A,B); s = size(C) % returns M-by-N-by-P. s = 300 1000 200 ...
Norm of First-order Iteration Func-count f(x) step optimality CG-iterations 0 4 38036.7 4.92e 04 1 8 38036.7 10 4.92e 04 0 2 12 38036.7 2.5 4.92e 04 0 3 16 ...
13 56 0.105681 2.21022e-10 1.43e 08. 14 60 0.105681 5.52556e-11 1.43e 08. Optimization stopped because the norm of the current step, 5.525560e-11,.
Can any one tell me what's the meaning of this value because it appears frequently in matlab, what's e and can i move from this representation of that value to ...
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What is the sum of the digits of the square of $ ext 111,111,111$ ? ... Using the standard multiplication algorithm, $111,111,111^2=12,345,678,987,654,321,$ ...
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y, so Equation (1.1) admits a unique solution on R, see [11] for more details. As. the exact ... system 14 TAYLOR4 (TP12) 1.000 9.1987e-11 10.000 487.39.
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... and RRAP have been proved to be NP-hard optimization problems [11,12], ... Rs 0.99997304 0.99997402 0.99997369 0.99997413 0.99997405 4.47953E 07 ...
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... 1.02E-05 10 1 0.1652 9.37E-06 11 1 0.1361 8.64E-06 12 1 0.1196 7.92E-06 ... 5.80E-05 24 1 0.1225 5.10E-05 25 1 0.1224 4.49E-05 26 1 0.1223 3.94E-05 ...